The Rolling Stones will most likely perform ‘Anybody Seen My Baby’ and ‘She’s A Rainbow’ on the upcoming South American tour for the first time in 18 years.
‘Anybody Seen My Baby’ was the first single from 1997 ‘Bridges To Babylon’ album. The song reached no 3 in the USA, no 6 in the UK and no 19 in Australia.
The other song the band has worked up is ‘She’s A Rainbow’. Coincidentally The Rolling Stones last performed both songs in Athens on September 16, 1998.
‘Anybody Seen My Baby’ has been performed 70 times in the past while ‘She’s A Rainbow’ is extremely rare live. The Stones have played it just 10 times.
Like the last tour, The Rolling Stones are using their official website to solicit requests. ‘Anybody Seen My Baby’ and ‘She’s A Rainbow’ have made the shortlist of four songs, which means they have rehearsed the songs in case they win the vote.
The other songs listed for the first show in Chile are ‘She’s So Cold’ (last played June 12, 2015 in Orlando) and ‘Like A Rolling Stone’ (last played November 22, 2014 in Auckland).
The first Rolling Stones show for 2016 in February 3, 2016 in Chile. It will be the band’s first show in Chile in 21 years.
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